X^2-17x=39

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Solution for X^2-17x=39 equation:



X^2-17X=39
We move all terms to the left:
X^2-17X-(39)=0
a = 1; b = -17; c = -39;
Δ = b2-4ac
Δ = -172-4·1·(-39)
Δ = 445
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{445}}{2*1}=\frac{17-\sqrt{445}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{445}}{2*1}=\frac{17+\sqrt{445}}{2} $

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